i) For n = 3; l = 0, 1 and 2For l = 0, ml = 0For l =1, ml = -1, 0+1For l = 2, ml = -2, -1, 0, +1, +2(ii) For 3d orbital, n = 3, l =2 For l =2, ml = -2, -1, 0, +1, +2(iii) 1 p is not possible because when n = 1, l = 0 only (For p, l = 1)2s is possible because when n =2, l = 0, 1(For s, l = 0) 2p is possible because when n=2, l = 0, (For p, l
Qs) = − 3 2 d ds 1 s2 +1. Hence, q(t) = L−1 {Q(s)} = − 3 2 L−1 ˆ d ds 1 s2 +1 ˙ = 3 2 tsint. (8) 8. Definition: The convolution of functions f(t) and g(t) is (f ∗ g)(t) = Z t 0 f(t − v)g(v)dv. (9) As we showed in class, the convolution is commutative: (f ∗ g)(t) = Z t 0 f(t − v)g(v)dv = Z t 0 g(t − v)f(v)dv = (g ∗ f)(t
Im now in Grade 12. When I was in Grade 11, I saw a question in the math club. (1, 3/2, 7/4, 15/8,) is converging to a limit. will go to zero as n goes to infinity, so the finite sum S will approach a / (1-r) as n goes to infinity. Thus the value of the infinite sum is a / (1-r), and this also proves that the infinite sum exists
Bilangankuantum spin (s) ⇒ Menyatakan arah putaran orbital. n = 3 ⇒ Menyatakan bahwa terdapat pada kulit 3. l = 2 ⇒ Menyatakan terletak pada subkulit d. s = + ⇒ Menyatakan arah putaran searah jarum jam. m = -1 ⇒ Menyatakan elektron terletak pada orbital kedua yang searah jarum jam yang artinya jumlah elektron adalah 2. Sehingga
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